無名人羣

I also think that...the standard answer is wrong...As we and many pll in this net analyse b4, there is a chance for 2 to stay alive in Case # 2 3 4 5, so 2 will disagree with 1 . Also 5 will disagree with 1 as he is sure to get one diamond in Case # 2 3 4 5. And so,this answer must be wrong.

Dear editor, As there is already a pll called 無名 ,could u pls just change my name to "無名人羣"???Thank you

sori..i've check my answer below..there are some "typing error" in the first mail i sent out, the forth paragraph ," For 5, he noes that...." ,in the third line . it should be "So,the same as 4,5 will agree if 2 give any diamond to 5"

I think why our answer is different from Robinson's one is because we "think" that 4 and 5 in this "game" will be the weakness as the process of distribution must be stopped in #3 4 5. So 1 will give 4 and 5 diamond to convince they agree 1 but not giving diamond to 3.

this solution must assume that they won't make any agreement, any dicussion b4. And also they need to be as clever as 1 ,if not, all the vote can be different from our answer.Also ,we need to assume that they won't have any "feeling" on others. That means, they all concern is only their life ,then t...閱讀更多

For # 1 2 3 4 5 5 noes actually in the whole process of distribution...he can't get more that 2 diamond as in # 3 4 5, 3 can do wht ever 3 like ,5 won't get any diamond in # 3 4 5.( # 4 5 actually is a case that will never happen.)In #2 3 4 5, 5 will get 1 diamond .If 1 only give 5 1 diamond, 5 may ...閱讀更多

i hv also discussed this question with my classmate and we conclude that the answer should be: 1 get 96 2 get 0 3 get 0 4 get 2 5 get 2 我們的推裡方式與Benson and Robinson 的大同小異。我們的process 如下: #1 2 3 4 5 96 0 0 2 2 #2 3 4 5 98 0 1 1 #3 4 5 100 0 0 #4 5 0 100 我們的answer 是assume 了他們會在不失去life 情況下冒最大的險. of cours...閱讀更多