Robinson

You're welcome. I don't know what your background is so you may find those books too easy. My apology if that's the case!

Hope this helps: H S M Coxeter, Introduction to Geometry G H Hardy, A Course of Pure Mathematics M Spivak, Calculus

Wedding Music L K: Congratulations on your wedding! I would suggest the second movement (adagio) from Mozart's Clarinet concerto (K622).

Hi SC Your first proof of the uphill/downhill problem (the one without using the intermediate value theorem) is really beautiful!! :) >數學與好女﹐不可兼得﹐捨數學而娶好女也< Hope you will find your love soon (if you haven't found one yet)

終於打到中文 不過係用手寫板，所以要好耐。 阿文： 我唔係住(口係)香港，所以留言個陣仲係黃昏。 希望你套莫札特漫畫早日出版，我第一個捧場！

文: Serenade No. 10 in B Major K361

笑到唞唔到氣 Some of the most recent popular songs have the same effect!

e^log2 = 2 Suppose log2 is rational, then we can say log2=p/q where p and q are integers. Then we have e^(p/q)=2, i.e. e^p=2^q, contradicting the fact that e is transcendental. Therefore log2 is irrational.

文: I only have two idols...you and Mozart! (No order of preference) >>以你超人的想像和創意，把莫扎特傳改成連載漫畫 Looking forward to it!

king mong sau wong tai ming ching cheung li man sau yi kwong lok chi wong sai kwan lau

1+1=0 in Z mod 2

I have never formally studied the concept of randomness. But as the discussion goes along I hope I will have new ideas to add.

New year is a good time to talk about aging... Life's Bell Curve At age 5 success is not peeing in your pants At age 10 success is having friends At age 16 success is having your driver's license At age 20 success is having sex At age 35 success is having money At age 50 success is having money At a...閱讀更多

>>為了愛情﹐金錢､名聲､享受､自由､生命全部都可以放棄。 >>//只能同意無論如何想死﹐為了愛人也要努力生存下去.什麼"為愛情而犧牲一切" , 什麼"金錢､名聲､享受､自由､生命都可不要", 都只是口號. // >>這不是口號﹐是實際有人做到的。 SC: Agree!

文: Your commentary is more exciting than the movie itself!

SC: I'm studying math there

SC: Do you live in Canada? Do you go to the U of T by any chance?

Alex Chu: Good one!

花少: 張海澎=吳蘭露?

吳蘭露大師一番金石良言，令小弟知道過錯，感激感激。 望大師大發慈悲，籍著智慧，引領特區七百多萬子民早日離開曠野，進入應許之地，則特區幸甚！萬民幸甚！ 小弟先行謝過。

>>又全能又靚仔嘅澤楷 問題：澤楷能否創造一間股價只升不跌的公司？ 如答案是否，他不是全能。 如答案是「能」，他不是全能。（他不能令該公司股價下跌。）

Oops...didn't show up as I want it to be

>>有餚無酒 Here we go! \___/ \_/ | __|__

What does this 花地瑪預言 say?

...or any time before the quiz actually take place

>>再想想如果將三千億分給700萬人時, 要點做? This is not hard...All goes to me! SC: There's a very simple solution to your "surprise quiz" problem...just give the quiz to the students without telling them about it the previous week

>>數學才是吃人的怪物 Only two kinds of people would say this: i)people who don't know anything about maths ii)maths majors >>哲學的意思就只是愛思考 有好奇心吧 不要以為是什麼怪物 Very true!

路人乙 >>因為1 死左, 2 講咩都唔夠過半數支持 This is not true...if 2 proposed 98,0,1,1 he'll get 3 votes (1 from himself and 1 each from 4 and 5) because if 2 gets killed then for sure 3 will propose 100,0,0 which 4 must vote for because otherwise he's going to die. 十三點 My reasoning is similar to George's...except th...閱讀更多

For convenience I'm calling the pirates #1,#2,..,#5 I am assuming an extra rule: If a pirate knows that #n+1's plan will give him the same number of coins as #n's plan, he will kill #n and take #n+1's plan. Then #1 should propose either of the following plans: #1 gets 97 coins, #3 get 1 coin and #4 ...閱讀更多

SC: It's only a minor technicality really. Anyway your proof is nice.

張海澎 I think he needs the fact that a is a root for x^2-(nb)x+(b^2-n) => P(a,b,n) in order to conclude that P(b,nb-a,n)

SC: Nice proof! Except that in line 2 of case 2 you might want to change the =>'s to <=>'s. 張海澎: I can't think of a different proof right now, but it's something interesting to think about.

Do we have any pure math major here?